首页> 外文OA文献 >The role of acid in the formation of hydrogen-bonded networks featuring 4,4'-dicarboxy-2,2'-bipyridine (H2dcbp): Synthesis, structural and magnetic characterisation of {[Cu(H2dcbp)Cl2].H2O}2 and [Cu(H2dcbp)(NO3)2(H2O)]
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The role of acid in the formation of hydrogen-bonded networks featuring 4,4'-dicarboxy-2,2'-bipyridine (H2dcbp): Synthesis, structural and magnetic characterisation of {[Cu(H2dcbp)Cl2].H2O}2 and [Cu(H2dcbp)(NO3)2(H2O)]

机译:酸在形成以4,4'-二羧基-2,2'-联吡啶(H2dcbp)为特征的氢键网络中的作用:{[Cu(H2dcbp)Cl2] .H2O} 2的合成,结构和磁性表征[铜(H2dcbp)(NO3)2(H2O)]

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摘要

Reported herein are the synthesis, structural and magnetic characterisation of two hydrogen-bonded networks featuring the 4,4?-dicarboxy-2,2?-bipyridine (H2dcbp) ligand: {[Cu(H2dcbp)(Cl)2]·H2O}2 1 and [Cu(H2dcbp)(NO3)2(H2O)] 2. Compounds 1 and 2 result from the reaction of CuCl2 and Cu(NO3)2, respectively, with H2dcbp under hydrothermal conditions in the presence of either HCl or HNO3. The acid ensures that H2dcbp remains protonated and provides the anions required for charge balance irrespective of Cu(II) precursor. Within 1 and 2 the H2dcbp ligand performs a dual role of Cu(II) coordination, via the 2,2?-bipyridine moiety, and propagates the formation of chains through hydrogen-bonding involving the peripheral 4,4?-dicarboxylic acid functionalities. Additional hydrogen bonding between the 4,4?-dicarboxylic acid groups, metal bound chloride and nitrate anions, in 1 and 2 respectively, and water molecules generate 3D networks. Variable temperature magnetic susceptibility measurements reveal very weak antiferromagnetic coupling between the Cu(II) centres across the chloride bridges in 1 (J = ?3.02 cm?1).
机译:本文报道了两个具有4,4′-二羧基-2,2′-联吡啶(H2dcbp)配体的氢键网络的合成,结构和磁性表征:{[Cu(H2dcbp)(Cl)2]·H2O} 2 1和[Cu(H2dcbp)(NO3)2(H2O)]2。化合物1和2分别是CuCl2和Cu(NO3)2与H2dcbp在HCl或HNO3存在下在水热条件下反应生成的。该酸可确保H2dcbp保持质子化,并提供电荷平衡所需的阴离子,而与Cu(II)前体无关。在1和2内,H 2 dcbp配体通过2,2′-联吡啶部分起Cu(Ⅱ)配位的双重作用,并通过涉及周边4,4′-二羧酸官能团的氢键传播链的形成。 4,4′-二羧酸基团,金属键合的氯离子和硝酸根阴离子分别与1和2之间的氢键和水分子产生3D网络。可变温度磁化率测量结果显示,跨氯化物桥的Cu(II)中心之间的反铁磁耦合非常弱,为1(J =?3.02 cm?1)。

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